5x^2-2540=0

Solution for 5x^2-2540=0 equation:

5x^2-2540=0

a = 5; b = 0; c = -2540;
Δ = b2-4ac
Δ = 02-4·5·(-2540)
Δ = 50800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{50800}=\sqrt{400*127}=\sqrt{400}*\sqrt{127}=20\sqrt{127}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{127}}{2*5}=\frac{0-20\sqrt{127}}{10}
=-\frac{20\sqrt{127}}{10}
=-2\sqrt{127}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{127}}{2*5}=\frac{0+20\sqrt{127}}{10}
=\frac{20\sqrt{127}}{10}
=2\sqrt{127}
$